Jawapan Latihan 2

 1.

                              RS = Rintangan pendarab
                              RM = Rintangan dalam meter d'Arsonval

   Fungsi rintangan pendarab : a)melanjutkan julat voltan meter
                                           b)Menghadkan arus melalui meter kepada arus pesongan skala
 

 2.

 RM = 100  ;  V = 10v  ;  ISP = 0.0001A

 Kepekaan,s = 1/ISP
                        = 1/0.0001A
                      = 10000

 RS = S x julat - RM
       = 10000 x 10 - 100
      = 99.99 k #

 3.


 

 RM = Rintangan dalam meter d'Arsonval
 RSH = Rintangan pirau

 Rintangan pirau digunakan sebagai laluan lain bagi arus yang diukur.

 4.RSH(ISH) = RMIM
    (100 - 0.0001)RSH = (105)(0.0001)
                           RSH =0.0105/99.9999
                                  = 0.105 m #

            atau

 n = I / IM
    = 100 / 0.0001
    = 1000k

 RSH = RM / n-1
        = 10.5 / 10000k - 1
        = 0.105m #

 5 .

 

 Meter ampere jenis Ayrton

 6.RM = 1k ,  IM = 0.00005 A
 a )Pada julat A4,  RSH = 1 + 9 + 90 + 900
                                      = 1000

                  RM / n-1 = RSH
                                  n = 2
                              n = IM / I4
                                      = 0.000025 A

 b )Pada julat A3,  RSH = 100  ,  RM = 1900
                        A3(100) = 0.00005(1900)
                                 A3 = 0.00005(19)
                                       = 0.95mA

 c )Pada julat A2  ,  RSH = 10 , RM = 1990
                                  A2 = 0.000005(1990) / 10
                                        = 9.95mA

 7.

 

 R1 = S x julat x RM
      = 20k x 1 - 1000
      = 19k #

 R2 = S x julat - RM
      = 20k x 10 - 1000
      = 199k #

 R3 = S x julat - RM
      = 20k x 1000 - 1000
      = 1999k #

 8.a ) i ) -  RSH digunakan untuk menambahkan aliran melalui D1 semasa separuh penuh
 kitar positif supaya lengkungan ciri diod lebih lurus
       - Diod D2 berfungsi atau terpincang balikan pada separuh kitaran positif dan hampir
 tiada kesan pada litar. Dan semasa kitar negatif, diod D2 terpincang depan dan menghasilkan
 laluan lain bagi arus pincang balikan yang akan mengalir melalui meter dan diod D1.

 ii) S = 2.5k  ,  RM = 150 , Ifsd = 0.0001 A  ,   VIN = 10 Vrms
                        ISH = RM(Ifsd) / RSH
                   Vpurata = 0.45(Vrms)
                              = 0.45 x 10
                              = 45v
                        RT = Sau x julat
                              = 2.5k(10)
                              = 25k #

                          IT = 1 / Sau
                                = 0.45 / 2.5k
                              = 0.00018 A
                        ISH = It - IM
                              = 0.00018 - 0.0001
                              = 0.00008 A
                      RSH = 150(0.0001) / 0.00008
                             = 187.5 #

 b )Dengan meter  ,  Sau = 2.5k  ,  RM = 150  , Julat = 10 Vrms
                    RTA = Sau x julat
                           = 2.5k x 10
                           = 25k
                     RR = Rb // RTA
                              = (10 x 25) / 35
                           = 7.143k

 Bacaan meter volt , VRB = E(RE) / (Ra + Re)
                                          = 10 (7.143k) / 5k + 7.143k
                                          = 5.9v #

 9. Ifsd = 1mA  , RM = 100  ,  RDL = 400  ,  Julat = 100 Vrms  ,  RSH = 100
 i )  ISH = RM(Ifsd) / RSH
            = 100(1m)/100
            =1mA
 IT = ISH + IM
     = 2mA
 RT = EAT / IT
 EAT = 0.9(Vpmkd)
        = 0.9(10)
        = 9
 maka;  RT = 9 / 2mA
                  = 4.5k
 RT = RS + RD + RM // RSH
 RS = RT - (RD + RM // RSH)
      = 4.5k - (200 + (100 x 100) / 200
      = 4.5k - 250
      = 4.25k #

 ii )  Sau = RT / julat
           = 4.5k / 10
           = 450

      Sat = Sau / 0.9
           = 450 / 0.9
           = 500

 10.i )  Rz = E / ISP - RM - RS
                = 3 / 0.00005 - 1000 - 2000
               = 60k - 3k
               = 57k #

     ii ) Pada 25%   ;     Rx = 57k + 3k / 0.25  - 60k
                                           = 180k #

           Pada 75%  ;      RX = 57k + 3k / 0.75 - 60
                                           = 20k #

     iii )  RX pada 50% skala penuh ;
                    RX = RZ + RM / p - (RZ + RM)
                          = 60/0.5 - 60
                          = 120 - 60
                          = 60
  maka didapati RX = Rmeter pada separuh skala penuh.
 
 
 
 

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